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- # Copyright 2015 Google Inc. All Rights Reserved.
- #
- # Licensed under the Apache License, Version 2.0 (the "License");
- # you may not use this file except in compliance with the License.
- # You may obtain a copy of the License at
- #
- # http://www.apache.org/licenses/LICENSE-2.0
- #
- # Unless required by applicable law or agreed to in writing, software
- # distributed under the License is distributed on an "AS IS" BASIS,
- # WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
- # See the License for the specific language governing permissions and
- # limitations under the License.
- """Verify that the generated code is valid code.
- This takes a line of code and "normalizes" it. I.e., it transforms the snippet
- into something that has the potential to compile.
- VerifyCode(): the main function exported by this module.
- """
- import ast
- import re
- import sys
- import textwrap
- class InternalError(Exception):
- """Internal error in verifying formatted code."""
- pass
- def VerifyCode(code):
- """Verify that the reformatted code is syntactically correct.
- Arguments:
- code: (unicode) The reformatted code snippet.
- Raises:
- SyntaxError if the code was reformatted incorrectly.
- """
- try:
- compile(textwrap.dedent(code).encode('UTF-8'), '<string>', 'exec')
- except SyntaxError:
- try:
- ast.parse(textwrap.dedent(code.lstrip('\n')).lstrip(), '<string>', 'exec')
- except SyntaxError:
- try:
- normalized_code = _NormalizeCode(code)
- compile(normalized_code.encode('UTF-8'), '<string>', 'exec')
- except SyntaxError:
- raise InternalError(sys.exc_info()[1])
- def _NormalizeCode(code):
- """Make sure that the code snippet is compilable."""
- code = textwrap.dedent(code.lstrip('\n')).lstrip()
- # Split the code to lines and get rid of all leading full-comment lines as
- # they can mess up the normalization attempt.
- lines = code.split('\n')
- i = 0
- for i, line in enumerate(lines):
- line = line.strip()
- if line and not line.startswith('#'):
- break
- code = '\n'.join(lines[i:]) + '\n'
- if re.match(r'(if|while|for|with|def|class|async|await)\b', code):
- code += '\n pass'
- elif re.match(r'(elif|else)\b', code):
- try:
- try_code = 'if True:\n pass\n' + code + '\n pass'
- ast.parse(
- textwrap.dedent(try_code.lstrip('\n')).lstrip(), '<string>', 'exec')
- code = try_code
- except SyntaxError:
- # The assumption here is that the code is on a single line.
- code = 'if True: pass\n' + code
- elif code.startswith('@'):
- code += '\ndef _():\n pass'
- elif re.match(r'try\b', code):
- code += '\n pass\nexcept:\n pass'
- elif re.match(r'(except|finally)\b', code):
- code = 'try:\n pass\n' + code + '\n pass'
- elif re.match(r'(return|yield)\b', code):
- code = 'def _():\n ' + code
- elif re.match(r'(continue|break)\b', code):
- code = 'while True:\n ' + code
- elif re.match(r'print\b', code):
- code = 'from __future__ import print_function\n' + code
- return code + '\n'
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